Package g3001_3100.s3083_existence_of_a_substring_in_a_string_and_its_reverse

Class Solution

java.lang.Object
g3001_3100.s3083_existence_of_a_substring_in_a_string_and_its_reverse.Solution
public class Solution extends java.lang.Object
3083 - Existence of a Substring in a String and Its Reverse.

Easy

Given a string s, find any substring of length 2 which is also present in the reverse of s.

Return true if such a substring exists, and false otherwise.

Example 1:

Input: s = “leetcode”

Output: true

Explanation: Substring "ee" is of length 2 which is also present in reverse(s) == "edocteel".

Example 2:

Input: s = “abcba”

Output: true

Explanation: All of the substrings of length 2 "ab", "bc", "cb", "ba" are also present in reverse(s) == "abcba".

Example 3:

Input: s = “abcd”

Output: false

Explanation: There is no substring of length 2 in s, which is also present in the reverse of s.

Constraints:

  • 1 <= s.length <= 100
  • s consists only of lowercase English letters.

  • Constructor Summary

    Constructors
    Constructor
    Description
    Solution()
     

  • Method Summary

    Modifier and Type
    Method
    Description
    boolean
    isSubstringPresent(java.lang.String s)
     

    Methods inherited from class java.lang.Object

    clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • isSubstringPresent

      public boolean isSubstringPresent(java.lang.String s)