Class Solution
java.lang.Object
g2801_2900.s2808_minimum_seconds_to_equalize_a_circular_array.Solution
2808 - Minimum Seconds to Equalize a Circular Array.<p>Medium</p>
<p>You are given a <strong>0-indexed</strong> array <code>nums</code> containing <code>n</code> integers.</p>
<p>At each second, you perform the following operation on the array:</p>
<ul>
<li>For every index <code>i</code> in the range <code>[0, n - 1]</code>, replace <code>nums[i]</code> with either <code>nums[i]</code>, <code>nums[(i - 1 + n) % n]</code>, or <code>nums[(i + 1) % n]</code>.</li>
</ul>
<p><strong>Note</strong> that all the elements get replaced simultaneously.</p>
<p>Return <em>the <strong>minimum</strong> number of seconds needed to make all elements in the array</em> <code>nums</code> <em>equal</em>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> nums = [1,2,1,2]</p>
<p><strong>Output:</strong> 1</p>
<p><strong>Explanation:</strong> We can equalize the array in 1 second in the following way:</p>
<ul>
<li>At 1<sup>st</sup> second, replace values at each index with [nums[3],nums[1],nums[3],nums[3]]. After replacement, nums = [2,2,2,2]. It can be proven that 1 second is the minimum amount of seconds needed for equalizing the array.</li>
</ul>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> nums = [2,1,3,3,2]</p>
<p><strong>Output:</strong> 2</p>
<p><strong>Explanation:</strong> We can equalize the array in 2 seconds in the following way:</p>
<ul>
<li>At 1<sup>st</sup> second, replace values at each index with [nums[0],nums[2],nums[2],nums[2],nums[3]]. After replacement, nums = [2,3,3,3,3].</li>
<li>At 2<sup>nd</sup> second, replace values at each index with [nums[1],nums[1],nums[2],nums[3],nums[4]]. After replacement, nums = [3,3,3,3,3].</li>
</ul>
<p>It can be proven that 2 seconds is the minimum amount of seconds needed for equalizing the array.</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> nums = [5,5,5,5]</p>
<p><strong>Output:</strong> 0</p>
<p><strong>Explanation:</strong> We don’t need to perform any operations as all elements in the initial array are the same.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= n == nums.length <= 10<sup>5</sup></code></li>
<li><code>1 <= nums[i] <= 10<sup>9</sup></code></li>
</ul>
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Solution
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minimumSeconds
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