Class Solution
java.lang.Object
g2401_2500.s2483_minimum_penalty_for_a_shop.Solution
2483 - Minimum Penalty for a Shop.<p>Medium</p>
<p>You are given the customer visit log of a shop represented by a <strong>0-indexed</strong> string <code>customers</code> consisting only of characters <code>'N'</code> and <code>'Y'</code>:</p>
<ul>
<li>if the <code>i<sup>th</sup></code> character is <code>'Y'</code>, it means that customers come at the <code>i<sup>th</sup></code> hour</li>
<li>whereas <code>'N'</code> indicates that no customers come at the <code>i<sup>th</sup></code> hour.</li>
</ul>
<p>If the shop closes at the <code>j<sup>th</sup></code> hour (<code>0 <= j <= n</code>), the <strong>penalty</strong> is calculated as follows:</p>
<ul>
<li>For every hour when the shop is open and no customers come, the penalty increases by <code>1</code>.</li>
<li>For every hour when the shop is closed and customers come, the penalty increases by <code>1</code>.</li>
</ul>
<p>Return <em>the <strong>earliest</strong> hour at which the shop must be closed to incur a <strong>minimum</strong> penalty.</em></p>
<p><strong>Note</strong> that if a shop closes at the <code>j<sup>th</sup></code> hour, it means the shop is closed at the hour <code>j</code>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> customers = “YYNY”</p>
<p><strong>Output:</strong> 2</p>
<p><strong>Explanation:</strong></p>
<ul>
<li>Closing the shop at the 0<sup>th</sup> hour incurs in 1+1+0+1 = 3 penalty.</li>
<li>Closing the shop at the 1<sup>st</sup> hour incurs in 0+1+0+1 = 2 penalty.</li>
<li>Closing the shop at the 2<sup>nd</sup> hour incurs in 0+0+0+1 = 1 penalty.</li>
<li>Closing the shop at the 3<sup>rd</sup> hour incurs in 0+0+1+1 = 2 penalty.</li>
<li>Closing the shop at the 4<sup>th</sup> hour incurs in 0+0+1+0 = 1 penalty.</li>
</ul>
<p>Closing the shop at 2<sup>nd</sup> or 4<sup>th</sup> hour gives a minimum penalty. Since 2 is earlier, the optimal closing time is 2.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> customers = “NNNNN”</p>
<p><strong>Output:</strong> 0</p>
<p><strong>Explanation:</strong> It is best to close the shop at the 0<sup>th</sup> hour as no customers arrive.</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> customers = “YYYY”</p>
<p><strong>Output:</strong> 4</p>
<p><strong>Explanation:</strong> It is best to close the shop at the 4<sup>th</sup> hour as customers arrive at each hour.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= customers.length <= 10<sup>5</sup></code></li>
<li><code>customers</code> consists only of characters <code>'Y'</code> and <code>'N'</code>.</li>
</ul>
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Solution
public Solution()
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Method Details
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bestClosingTime
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