Class Solution
java.lang.Object
g2401_2500.s2406_divide_intervals_into_minimum_number_of_groups.Solution
2406 - Divide Intervals Into Minimum Number of Groups.<p>Medium</p>
<p>You are given a 2D integer array <code>intervals</code> where <code>intervals[i] = [left<sub>i</sub>, right<sub>i</sub>]</code> represents the <strong>inclusive</strong> interval <code>[left<sub>i</sub>, right<sub>i</sub>]</code>.</p>
<p>You have to divide the intervals into one or more <strong>groups</strong> such that each interval is in <strong>exactly</strong> one group, and no two intervals that are in the same group <strong>intersect</strong> each other.</p>
<p>Return <em>the <strong>minimum</strong> number of groups you need to make</em>.</p>
<p>Two intervals <strong>intersect</strong> if there is at least one common number between them. For example, the intervals <code>[1, 5]</code> and <code>[5, 8]</code> intersect.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> intervals = [[5,10],[6,8],[1,5],[2,3],[1,10]]</p>
<p><strong>Output:</strong> 3</p>
<p><strong>Explanation:</strong> We can divide the intervals into the following groups:</p>
<ul>
<li>
<p>Group 1: [1, 5], [6, 8].</p>
</li>
<li>
<p>Group 2: [2, 3], [5, 10].</p>
</li>
<li>
<p>Group 3: [1, 10].</p>
</li>
</ul>
<p>It can be proven that it is not possible to divide the intervals into fewer than 3 groups.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> intervals = [[1,3],[5,6],[8,10],[11,13]]</p>
<p><strong>Output:</strong> 1</p>
<p><strong>Explanation:</strong> None of the intervals overlap, so we can put all of them in one group.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= intervals.length <= 10<sup>5</sup></code></li>
<li><code>intervals[i].length == 2</code></li>
<li><code>1 <= left<sub>i</sub> <= right<sub>i</sub> <= 10<sup>6</sup></code></li>
</ul>
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Solution
public Solution()
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Method Details
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minGroups
public int minGroups(int[][] intervals)
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