java.lang.Object
g2201_2300.s2250_count_number_of_rectangles_containing_each_point.Solution

public class Solution extends Object
2250 - Count Number of Rectangles Containing Each Point.<p>Medium</p> <p>You are given a 2D integer array <code>rectangles</code> where <code>rectangles[i] = [l<sub>i</sub>, h<sub>i</sub>]</code> indicates that <code>i<sup>th</sup></code> rectangle has a length of <code>l<sub>i</sub></code> and a height of <code>h<sub>i</sub></code>. You are also given a 2D integer array <code>points</code> where <code>points[j] = [x<sub>j</sub>, y<sub>j</sub>]</code> is a point with coordinates <code>(x<sub>j</sub>, y<sub>j</sub>)</code>.</p> <p>The <code>i<sup>th</sup></code> rectangle has its <strong>bottom-left corner</strong> point at the coordinates <code>(0, 0)</code> and its <strong>top-right corner</strong> point at <code>(l<sub>i</sub>, h<sub>i</sub>)</code>.</p> <p>Return <em>an integer array</em> <code>count</code> <em>of length</em> <code>points.length</code> <em>where</em> <code>count[j]</code> <em>is the number of rectangles that <strong>contain</strong> the</em> <code>j<sup>th</sup></code> <em>point.</em></p> <p>The <code>i<sup>th</sup></code> rectangle <strong>contains</strong> the <code>j<sup>th</sup></code> point if <code>0 <= x<sub>j</sub> <= l<sub>i</sub></code> and <code>0 <= y<sub>j</sub> <= h<sub>i</sub></code>. Note that points that lie on the <strong>edges</strong> of a rectangle are also considered to be contained by that rectangle.</p> <p><strong>Example 1:</strong></p> <p><img src="https://assets.leetcode.com/uploads/2022/03/02/example1.png" alt="" /></p> <p><strong>Input:</strong> rectangles = [[1,2],[2,3],[2,5]], points = [[2,1],[1,4]]</p> <p><strong>Output:</strong> [2,1]</p> <p><strong>Explanation:</strong></p> <p>The first rectangle contains no points.</p> <p>The second rectangle contains only the point (2, 1).</p> <p>The third rectangle contains the points (2, 1) and (1, 4).</p> <p>The number of rectangles that contain the point (2, 1) is 2.</p> <p>The number of rectangles that contain the point (1, 4) is 1.</p> <p>Therefore, we return [2, 1].</p> <p><strong>Example 2:</strong></p> <p><img src="https://assets.leetcode.com/uploads/2022/03/02/example2.png" alt="" /></p> <p><strong>Input:</strong> rectangles = [[1,1],[2,2],[3,3]], points = [[1,3],[1,1]]</p> <p><strong>Output:</strong> [1,3]</p> <p><strong>Explanation:</strong></p> <p>The first rectangle contains only the point (1, 1).</p> <p>The second rectangle contains only the point (1, 1).</p> <p>The third rectangle contains the points (1, 3) and (1, 1).</p> <p>The number of rectangles that contain the point (1, 3) is 1.</p> <p>The number of rectangles that contain the point (1, 1) is 3.</p> <p>Therefore, we return [1, 3].</p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= rectangles.length, points.length <= 5 * 10<sup>4</sup></code></li> <li><code>rectangles[i].length == points[j].length == 2</code></li> <li><code>1 <= l<sub>i</sub>, x<sub>j</sub> <= 10<sup>9</sup></code></li> <li><code>1 <= h<sub>i</sub>, y<sub>j</sub> <= 100</code></li> <li>All the <code>rectangles</code> are <strong>unique</strong>.</li> <li>All the <code>points</code> are <strong>unique</strong>.</li> </ul>
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • countRectangles

      public int[] countRectangles(int[][] rectangles, int[][] points)