Class Solution
java.lang.Object
g2101_2200.s2163_minimum_difference_in_sums_after_removal_of_elements.Solution
2163 - Minimum Difference in Sums After Removal of Elements.<p>Hard</p>
<p>You are given a <strong>0-indexed</strong> integer array <code>nums</code> consisting of <code>3 * n</code> elements.</p>
<p>You are allowed to remove any <strong>subsequence</strong> of elements of size <strong>exactly</strong> <code>n</code> from <code>nums</code>. The remaining <code>2 * n</code> elements will be divided into two <strong>equal</strong> parts:</p>
<ul>
<li>The first <code>n</code> elements belonging to the first part and their sum is <code>sum<sub>first</sub></code>.</li>
<li>The next <code>n</code> elements belonging to the second part and their sum is <code>sum<sub>second</sub></code>.</li>
</ul>
<p>The <strong>difference in sums</strong> of the two parts is denoted as <code>sum<sub>first</sub> - sum<sub>second</sub></code>.</p>
<ul>
<li>For example, if <code>sum<sub>first</sub> = 3</code> and <code>sum<sub>second</sub> = 2</code>, their difference is <code>1</code>.</li>
<li>Similarly, if <code>sum<sub>first</sub> = 2</code> and <code>sum<sub>second</sub> = 3</code>, their difference is <code>-1</code>.</li>
</ul>
<p>Return <em>the <strong>minimum difference</strong> possible between the sums of the two parts after the removal of</em> <code>n</code> <em>elements</em>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> nums = [3,1,2]</p>
<p><strong>Output:</strong> -1</p>
<p><strong>Explanation:</strong> Here, nums has 3 elements, so n = 1.</p>
<p>Thus we have to remove 1 element from nums and divide the array into two equal parts.</p>
<ul>
<li>
<p>If we remove nums[0] = 3, the array will be [1,2]. The difference in sums of the two parts will be 1 - 2 = -1.</p>
</li>
<li>
<p>If we remove nums[1] = 1, the array will be [3,2]. The difference in sums of the two parts will be 3 - 2 = 1.</p>
</li>
<li>
<p>If we remove nums[2] = 2, the array will be [3,1]. The difference in sums of the two parts will be 3 - 1 = 2.</p>
</li>
</ul>
<p>The minimum difference between sums of the two parts is min(-1,1,2) = -1.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> nums = [7,9,5,8,1,3]</p>
<p><strong>Output:</strong> 1</p>
<p><strong>Explanation:</strong> Here n = 2. So we must remove 2 elements and divide the remaining array into two parts containing two elements each.</p>
<p>If we remove nums[2] = 5 and nums[3] = 8, the resultant array will be [7,9,1,3]. The difference in sums will be (7+9) - (1+3) = 12.</p>
<p>To obtain the minimum difference, we should remove nums[1] = 9 and nums[4] = 1. The resultant array becomes [7,5,8,3]. The difference in sums of the two parts is (7+5) - (8+3) = 1.</p>
<p>It can be shown that it is not possible to obtain a difference smaller than 1.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>nums.length == 3 * n</code></li>
<li><code>1 <= n <= 10<sup>5</sup></code></li>
<li><code>1 <= nums[i] <= 10<sup>5</sup></code></li>
</ul>
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Solution
public Solution()
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minimumDifference
public long minimumDifference(int[] nums)
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