Class Solution
java.lang.Object
g2101_2200.s2115_find_all_possible_recipes_from_given_supplies.Solution
2115 - Find All Possible Recipes from Given Supplies.<p>Medium</p>
<p>You have information about <code>n</code> different recipes. You are given a string array <code>recipes</code> and a 2D string array <code>ingredients</code>. The <code>i<sup>th</sup></code> recipe has the name <code>recipes[i]</code>, and you can <strong>create</strong> it if you have <strong>all</strong> the needed ingredients from <code>ingredients[i]</code>. Ingredients to a recipe may need to be created from <strong>other</strong> recipes, i.e., <code>ingredients[i]</code> may contain a string that is in <code>recipes</code>.</p>
<p>You are also given a string array <code>supplies</code> containing all the ingredients that you initially have, and you have an infinite supply of all of them.</p>
<p>Return <em>a list of all the recipes that you can create.</em> You may return the answer in <strong>any order</strong>.</p>
<p>Note that two recipes may contain each other in their ingredients.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> recipes = [“bread”], ingredients = [[“yeast”,“flour”]], supplies = [“yeast”,“flour”,“corn”]</p>
<p><strong>Output:</strong> [“bread”]</p>
<p><strong>Explanation:</strong> We can create “bread” since we have the ingredients “yeast” and “flour”.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> recipes = [“bread”,“sandwich”], ingredients = [[“yeast”,“flour”],[“bread”,“meat”]], supplies = [“yeast”,“flour”,“meat”]</p>
<p><strong>Output:</strong> [“bread”,“sandwich”]</p>
<p><strong>Explanation:</strong></p>
<p>We can create “bread” since we have the ingredients “yeast” and “flour”.</p>
<p>We can create “sandwich” since we have the ingredient “meat” and can create the ingredient “bread”.</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> recipes = [“bread”,“sandwich”,“burger”], ingredients = [[“yeast”,“flour”],[“bread”,“meat”],[“sandwich”,“meat”,“bread”]], supplies = [“yeast”,“flour”,“meat”]</p>
<p><strong>Output:</strong> [“bread”,“sandwich”,“burger”]</p>
<p><strong>Explanation:</strong></p>
<p>We can create “bread” since we have the ingredients “yeast” and “flour”.</p>
<p>We can create “sandwich” since we have the ingredient “meat” and can create the ingredient “bread”.</p>
<p>We can create “burger” since we have the ingredient “meat” and can create the ingredients “bread” and “sandwich”.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>n == recipes.length == ingredients.length</code></li>
<li><code>1 <= n <= 100</code></li>
<li><code>1 <= ingredients[i].length, supplies.length <= 100</code></li>
<li><code>1 <= recipes[i].length, ingredients[i][j].length, supplies[k].length <= 10</code></li>
<li><code>recipes[i], ingredients[i][j]</code>, and <code>supplies[k]</code> consist only of lowercase English letters.</li>
<li>All the values of <code>recipes</code> and <code>supplies</code> combined are unique.</li>
<li>Each <code>ingredients[i]</code> does not contain any duplicate values.</li>
</ul>
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Constructor Summary
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Solution
public Solution()
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Method Details
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findAllRecipes
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