Class Solution
java.lang.Object
g2001_2100.s2068_check_whether_two_strings_are_almost_equivalent.Solution
2068 - Check Whether Two Strings are Almost Equivalent.<p>Easy</p>
<p>Two strings <code>word1</code> and <code>word2</code> are considered <strong>almost equivalent</strong> if the differences between the frequencies of each letter from <code>'a'</code> to <code>'z'</code> between <code>word1</code> and <code>word2</code> is <strong>at most</strong> <code>3</code>.</p>
<p>Given two strings <code>word1</code> and <code>word2</code>, each of length <code>n</code>, return <code>true</code> <em>if</em> <code>word1</code> <em>and</em> <code>word2</code> <em>are <strong>almost equivalent</strong> , or</em> <code>false</code> <em>otherwise</em>.</p>
<p>The <strong>frequency</strong> of a letter <code>x</code> is the number of times it occurs in the string.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> word1 = “aaaa”, word2 = “bccb”</p>
<p><strong>Output:</strong> false</p>
<p><strong>Explanation:</strong> There are 4 ’a’s in “aaaa” but 0 ’a’s in “bccb”.</p>
<p>The difference is 4, which is more than the allowed 3.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> word1 = “abcdeef”, word2 = “abaaacc”</p>
<p><strong>Output:</strong> true</p>
<p><strong>Explanation:</strong> The differences between the frequencies of each letter in word1 and word2 are at most 3:</p>
<ul>
<li>
<p>‘a’ appears 1 time in word1 and 4 times in word2. The difference is 3.</p>
</li>
<li>
<p>‘b’ appears 1 time in word1 and 1 time in word2. The difference is 0.</p>
</li>
<li>
<p>‘c’ appears 1 time in word1 and 2 times in word2. The difference is 1.</p>
</li>
<li>
<p>‘d’ appears 1 time in word1 and 0 times in word2. The difference is 1.</p>
</li>
<li>
<p>‘e’ appears 2 times in word1 and 0 times in word2. The difference is 2.</p>
</li>
<li>
<p>‘f’ appears 1 time in word1 and 0 times in word2. The difference is 1.</p>
</li>
</ul>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> word1 = “cccddabba”, word2 = “babababab”</p>
<p><strong>Output:</strong> true</p>
<p><strong>Explanation:</strong> The differences between the frequencies of each letter in word1 and word2 are at most 3:</p>
<ul>
<li>
<p>‘a’ appears 2 times in word1 and 4 times in word2. The difference is 2.</p>
</li>
<li>
<p>‘b’ appears 2 times in word1 and 5 times in word2. The difference is 3.</p>
</li>
<li>
<p>‘c’ appears 3 times in word1 and 0 times in word2. The difference is 3.</p>
</li>
<li>
<p>‘d’ appears 2 times in word1 and 0 times in word2. The difference is 2.</p>
</li>
</ul>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>n == word1.length == word2.length</code></li>
<li><code>1 <= n <= 100</code></li>
<li><code>word1</code> and <code>word2</code> consist only of lowercase English letters.</li>
</ul>
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Constructor Summary
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Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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checkAlmostEquivalent
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