Class Solution
java.lang.Object
g1901_2000.s1953_maximum_number_of_weeks_for_which_you_can_work.Solution
1953 - Maximum Number of Weeks for Which You Can Work.<p>Medium</p>
<p>There are <code>n</code> projects numbered from <code>0</code> to <code>n - 1</code>. You are given an integer array <code>milestones</code> where each <code>milestones[i]</code> denotes the number of milestones the <code>i<sup>th</sup></code> project has.</p>
<p>You can work on the projects following these two rules:</p>
<ul>
<li>Every week, you will finish <strong>exactly one</strong> milestone of <strong>one</strong> project. You <strong>must</strong> work every week.</li>
<li>You <strong>cannot</strong> work on two milestones from the same project for two <strong>consecutive</strong> weeks.</li>
</ul>
<p>Once all the milestones of all the projects are finished, or if the only milestones that you can work on will cause you to violate the above rules, you will <strong>stop working</strong>. Note that you may not be able to finish every project’s milestones due to these constraints.</p>
<p>Return <em>the <strong>maximum</strong> number of weeks you would be able to work on the projects without violating the rules mentioned above</em>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> milestones = [1,2,3]</p>
<p><strong>Output:</strong> 6</p>
<p><strong>Explanation:</strong> One possible scenario is:</p>
<ul>
<li>
<p>During the 1<sup>st</sup> week, you will work on a milestone of project 0.</p>
</li>
<li>
<p>During the 2<sup>nd</sup> week, you will work on a milestone of project 2.</p>
</li>
<li>
<p>During the 3<sup>rd</sup> week, you will work on a milestone of project 1.</p>
</li>
<li>
<p>During the 4<sup>th</sup> week, you will work on a milestone of project 2.</p>
</li>
<li>
<p>During the 5<sup>th</sup> week, you will work on a milestone of project 1.</p>
</li>
<li>
<p>During the 6<sup>th</sup> week, you will work on a milestone of project 2.</p>
</li>
</ul>
<p>The total number of weeks is 6.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> milestones = [5,2,1]</p>
<p><strong>Output:</strong> 7</p>
<p><strong>Explanation:</strong> One possible scenario is:</p>
<ul>
<li>
<p>During the 1<sup>st</sup> week, you will work on a milestone of project 0.</p>
</li>
<li>
<p>During the 2<sup>nd</sup> week, you will work on a milestone of project 1.</p>
</li>
<li>
<p>During the 3<sup>rd</sup> week, you will work on a milestone of project 0.</p>
</li>
<li>
<p>During the 4<sup>th</sup> week, you will work on a milestone of project 1.</p>
</li>
<li>
<p>During the 5<sup>th</sup> week, you will work on a milestone of project 0.</p>
</li>
<li>
<p>During the 6<sup>th</sup> week, you will work on a milestone of project 2.</p>
</li>
<li>
<p>During the 7<sup>th</sup> week, you will work on a milestone of project 0.</p>
</li>
</ul>
<p>The total number of weeks is 7. Note that you cannot work on the last milestone of project 0 on 8<sup>th</sup> week because it would violate the rules. Thus, one milestone in project 0 will remain unfinished.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>n == milestones.length</code></li>
<li><code>1 <= n <= 10<sup>5</sup></code></li>
<li><code>1 <= milestones[i] <= 10<sup>9</sup></code></li>
</ul>
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Solution
public Solution()
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Method Details
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numberOfWeeks
public long numberOfWeeks(int[] milestones)
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