java.lang.Object
g1601_1700.s1642_furthest_building_you_can_reach.Solution

public class Solution extends Object
1642 - Furthest Building You Can Reach.<p>Medium</p> <p>You are given an integer array <code>heights</code> representing the heights of buildings, some <code>bricks</code>, and some <code>ladders</code>.</p> <p>You start your journey from building <code>0</code> and move to the next building by possibly using bricks or ladders.</p> <p>While moving from building <code>i</code> to building <code>i+1</code> ( <strong>0-indexed</strong> ),</p> <ul> <li>If the current building&rsquo;s height is <strong>greater than or equal</strong> to the next building&rsquo;s height, you do <strong>not</strong> need a ladder or bricks.</li> <li>If the current building&rsquo;s height is <strong>less than</strong> the next building&rsquo;s height, you can either use <strong>one ladder</strong> or <code>(h[i+1] - h[i])</code> <strong>bricks</strong>.</li> </ul> <p><em>Return the furthest building index (0-indexed) you can reach if you use the given ladders and bricks optimally.</em></p> <p><strong>Example 1:</strong></p> <p><img src="https://assets.leetcode.com/uploads/2020/10/27/q4.gif" alt="" /></p> <p><strong>Input:</strong> heights = [4,2,7,6,9,14,12], bricks = 5, ladders = 1</p> <p><strong>Output:</strong> 4</p> <p><strong>Explanation:</strong> Starting at building 0, you can follow these steps:</p> <ul> <li> <p>Go to building 1 without using ladders nor bricks since 4 >= 2.</p> </li> <li> <p>Go to building 2 using 5 bricks. You must use either bricks or ladders because 2 < 7.</p> </li> <li> <p>Go to building 3 without using ladders nor bricks since 7 >= 6.</p> </li> <li> <p>Go to building 4 using your only ladder. You must use either bricks or ladders because 6 < 9.</p> </li> </ul> <p>It is impossible to go beyond building 4 because you do not have any more bricks or ladders.</p> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> heights = [4,12,2,7,3,18,20,3,19], bricks = 10, ladders = 2</p> <p><strong>Output:</strong> 7</p> <p><strong>Example 3:</strong></p> <p><strong>Input:</strong> heights = [14,3,19,3], bricks = 17, ladders = 0</p> <p><strong>Output:</strong> 3</p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= heights.length <= 10<sup>5</sup></code></li> <li><code>1 <= heights[i] <= 10<sup>6</sup></code></li> <li><code>0 <= bricks <= 10<sup>9</sup></code></li> <li><code>0 <= ladders <= heights.length</code></li> </ul>
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • furthestBuilding

      public int furthestBuilding(int[] heights, int bricks, int ladders)