Class Solution
java.lang.Object
g1401_1500.s1455_check_if_a_word_occurs_as_a_prefix_of_any_word_in_a_sentence.Solution
1455 - Check If a Word Occurs As a Prefix of Any Word in a Sentence.<p>Easy</p>
<p>Given a <code>sentence</code> that consists of some words separated by a <strong>single space</strong> , and a <code>searchWord</code>, check if <code>searchWord</code> is a prefix of any word in <code>sentence</code>.</p>
<p>Return <em>the index of the word in</em> <code>sentence</code> <em>( <strong>1-indexed</strong> ) where</em> <code>searchWord</code> <em>is a prefix of this word</em>. If <code>searchWord</code> is a prefix of more than one word, return the index of the first word <strong>(minimum index)</strong>. If there is no such word return <code>-1</code>.</p>
<p>A <strong>prefix</strong> of a string <code>s</code> is any leading contiguous substring of <code>s</code>.</p>
<p><strong>Example 1:</strong></p>
<p><strong>Input:</strong> sentence = “i love eating burger”, searchWord = “burg”</p>
<p><strong>Output:</strong> 4</p>
<p><strong>Explanation:</strong> “burg” is prefix of “burger” which is the 4th word in the sentence.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> sentence = “this problem is an easy problem”, searchWord = “pro”</p>
<p><strong>Output:</strong> 2</p>
<p><strong>Explanation:</strong> “pro” is prefix of “problem” which is the 2nd and the 6th word in the sentence, but we return 2 as it’s the minimal index.</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> sentence = “i am tired”, searchWord = “you”</p>
<p><strong>Output:</strong> -1</p>
<p><strong>Explanation:</strong> “you” is not a prefix of any word in the sentence.</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>1 <= sentence.length <= 100</code></li>
<li><code>1 <= searchWord.length <= 10</code></li>
<li><code>sentence</code> consists of lowercase English letters and spaces.</li>
<li><code>searchWord</code> consists of lowercase English letters.</li>
</ul>
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Constructor Summary
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Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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isPrefixOfWord
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