Package g0901_1000.s0922_sort_array_by_parity_ii

Class Solution

java.lang.Object

g0901_1000.s0922_sort_array_by_parity_ii.Solution

public class Solution
extends Object

922 - Sort Array By Parity II.<p>Easy</p> <p>Given an array of integers <code>nums</code>, half of the integers in <code>nums</code> are <strong>odd</strong> , and the other half are <strong>even</strong>.</p> <p>Sort the array so that whenever <code>nums[i]</code> is odd, <code>i</code> is <strong>odd</strong> , and whenever <code>nums[i]</code> is even, <code>i</code> is <strong>even</strong>.</p> <p>Return <em>any answer array that satisfies this condition</em>.</p> <p><strong>Example 1:</strong></p> <p><strong>Input:</strong> nums = [4,2,5,7]</p> <p><strong>Output:</strong> [4,5,2,7]</p> <p><strong>Explanation:</strong> [4,7,2,5], [2,5,4,7], [2,7,4,5] would also have been accepted.</p> <p><strong>Example 2:</strong></p> <p><strong>Input:</strong> nums = [2,3]</p> <p><strong>Output:</strong> [2,3]</p> <p><strong>Constraints:</strong></p> <ul> <li><code>2 <= nums.length <= 2 * 10⁴</code></li> <li><code>nums.length</code> is even.</li> <li>Half of the integers in <code>nums</code> are even.</li> <li><code>0 <= nums[i] <= 1000</code></li> </ul> <p><strong>Follow Up:</strong> Could you solve it in-place?</p>

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
int[]	sortArrayByParityII(int[] nums)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

sortArrayByParityII

public int[] sortArrayByParityII(int[] nums)