Class Solution
java.lang.Object
g0801_0900.s0861_score_after_flipping_matrix.Solution
861 - Score After Flipping Matrix.<p>Medium</p>
<p>You are given an <code>m x n</code> binary matrix <code>grid</code>.</p>
<p>A <strong>move</strong> consists of choosing any row or column and toggling each value in that row or column (i.e., changing all <code>0</code>’s to <code>1</code>’s, and all <code>1</code>’s to <code>0</code>’s).</p>
<p>Every row of the matrix is interpreted as a binary number, and the <strong>score</strong> of the matrix is the sum of these numbers.</p>
<p>Return <em>the highest possible <strong>score</strong> after making any number of <strong>moves</strong> (including zero moves)</em>.</p>
<p><strong>Example 1:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2021/07/23/lc-toogle1.jpg" alt="" /></p>
<p><strong>Input:</strong> grid = [[0,0,1,1],[1,0,1,0],[1,1,0,0]]</p>
<p><strong>Output:</strong> 39</p>
<p><strong>Explanation:</strong> 0b1111 + 0b1001 + 0b1111 = 15 + 9 + 15 = 39</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> grid = [[0]]</p>
<p><strong>Output:</strong> 1</p>
<p><strong>Constraints:</strong></p>
<ul>
<li><code>m == grid.length</code></li>
<li><code>n == grid[i].length</code></li>
<li><code>1 <= m, n <= 20</code></li>
<li><code>grid[i][j]</code> is either <code>0</code> or <code>1</code>.</li>
</ul>
-
Constructor Summary
Constructors -
Method Summary
-
Constructor Details
-
Solution
public Solution()
-
-
Method Details
-
matrixScore
public int matrixScore(int[][] grid)
-