Class Solution
java.lang.Object
g0101_0200.s0109_convert_sorted_list_to_binary_search_tree.Solution
109 - Convert Sorted List to Binary Search Tree.<p>Medium</p>
<p>Given the <code>head</code> of a singly linked list where elements are <strong>sorted in ascending order</strong> , convert it to a height balanced BST.</p>
<p>For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of <em>every</em> node never differ by more than 1.</p>
<p><strong>Example 1:</strong></p>
<p><img src="https://assets.leetcode.com/uploads/2020/08/17/linked.jpg" alt="" /></p>
<p><strong>Input:</strong> head = [-10,-3,0,5,9]</p>
<p><strong>Output:</strong> [0,-3,9,-10,null,5]</p>
<p><strong>Explanation:</strong> One possible answer is [0,-3,9,-10,null,5], which represents the shown height balanced BST.</p>
<p><strong>Example 2:</strong></p>
<p><strong>Input:</strong> head = []</p>
<p><strong>Output:</strong> []</p>
<p><strong>Example 3:</strong></p>
<p><strong>Input:</strong> head = [0]</p>
<p><strong>Output:</strong> [0]</p>
<p><strong>Example 4:</strong></p>
<p><strong>Input:</strong> head = [1,3]</p>
<p><strong>Output:</strong> [3,1]</p>
<p><strong>Constraints:</strong></p>
<ul>
<li>The number of nodes in <code>head</code> is in the range <code>[0, 2 * 10<sup>4</sup>]</code>.</li>
<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>
</ul>
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Constructor Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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sortedListToBST
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