Class Solution


  • public class Solution
    extends Object
    2385 - Amount of Time for Binary Tree to Be Infected\. Medium You are given the `root` of a binary tree with **unique** values, and an integer `start`. At minute `0`, an **infection** starts from the node with value `start`. Each minute, a node becomes infected if: * The node is currently uninfected. * The node is adjacent to an infected node. Return _the number of minutes needed for the entire tree to be infected._ **Example 1:** ![](https://assets.leetcode.com/uploads/2022/06/25/image-20220625231744-1.png) **Input:** root = [1,5,3,null,4,10,6,9,2], start = 3 **Output:** 4 **Explanation:** The following nodes are infected during: - Minute 0: Node 3 - Minute 1: Nodes 1, 10 and 6 - Minute 2: Node 5 - Minute 3: Node 4 - Minute 4: Nodes 9 and 2 It takes 4 minutes for the whole tree to be infected so we return 4. **Example 2:** ![](https://assets.leetcode.com/uploads/2022/06/25/image-20220625231812-2.png) **Input:** root = [1], start = 1 **Output:** 0 **Explanation:** At minute 0, the only node in the tree is infected so we return 0. **Constraints:** * The number of nodes in the tree is in the range [1, 105]. * 1 <= Node.val <= 105 * Each node has a **unique** value. * A node with a value of `start` exists in the tree.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • amountOfTime

        public int amountOfTime​(TreeNode root,
                                int start)