Class Solution


  • public class Solution
    extends Object
    2278 - Percentage of Letter in String\. Easy Given a string `s` and a character `letter`, return _the **percentage** of characters in_ `s` _that equal_ `letter` _**rounded down** to the nearest whole percent._ **Example 1:** **Input:** s = "foobar", letter = "o" **Output:** 33 **Explanation:** The percentage of characters in s that equal the letter 'o' is 2 / 6 \* 100% = 33% when rounded down, so we return 33. **Example 2:** **Input:** s = "jjjj", letter = "k" **Output:** 0 **Explanation:** The percentage of characters in s that equal the letter 'k' is 0%, so we return 0. **Constraints:** * `1 <= s.length <= 100` * `s` consists of lowercase English letters. * `letter` is a lowercase English letter.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • percentageLetter

        public int percentageLetter​(String s,
                                    char letter)