Class Solution


  • public class Solution
    extends Object
    2085 - Count Common Words With One Occurrence\. Easy Given two string arrays `words1` and `words2`, return _the number of strings that appear **exactly once** in **each** of the two arrays._ **Example 1:** **Input:** words1 = ["leetcode","is","amazing","as","is"], words2 = ["amazing","leetcode","is"] **Output:** 2 **Explanation:** - "leetcode" appears exactly once in each of the two arrays. We count this string. - "amazing" appears exactly once in each of the two arrays. We count this string. - "is" appears in each of the two arrays, but there are 2 occurrences of it in words1. We do not count this string. - "as" appears once in words1, but does not appear in words2. We do not count this string. Thus, there are 2 strings that appear exactly once in each of the two arrays. **Example 2:** **Input:** words1 = ["b","bb","bbb"], words2 = ["a","aa","aaa"] **Output:** 0 **Explanation:** There are no strings that appear in each of the two arrays. **Example 3:** **Input:** words1 = ["a","ab"], words2 = ["a","a","a","ab"] **Output:** 1 **Explanation:** The only string that appears exactly once in each of the two arrays is "ab". **Constraints:** * `1 <= words1.length, words2.length <= 1000` * `1 <= words1[i].length, words2[j].length <= 30` * `words1[i]` and `words2[j]` consists only of lowercase English letters.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • countWords

        public int countWords​(String[] words1,
                              String[] words2)