public class Solution
extends Object
1835 - Find XOR Sum of All Pairs Bitwise AND\.
Hard
The **XOR sum** of a list is the bitwise `XOR` of all its elements. If the list only contains one element, then its **XOR sum** will be equal to this element.
* For example, the **XOR sum** of `[1,2,3,4]` is equal to `1 XOR 2 XOR 3 XOR 4 = 4`, and the **XOR sum** of `[3]` is equal to `3`.
You are given two **0-indexed** arrays `arr1` and `arr2` that consist only of non-negative integers.
Consider the list containing the result of `arr1[i] AND arr2[j]` (bitwise `AND`) for every `(i, j)` pair where `0 <= i < arr1.length` and `0 <= j < arr2.length`.
Return _the **XOR sum** of the aforementioned list_.
**Example 1:**
**Input:** arr1 = [1,2,3], arr2 = [6,5]
**Output:** 0
**Explanation:** The list = [1 AND 6, 1 AND 5, 2 AND 6, 2 AND 5, 3 AND 6, 3 AND 5] = [0,1,2,0,2,1]. The XOR sum = 0 XOR 1 XOR 2 XOR 0 XOR 2 XOR 1 = 0.
**Example 2:**
**Input:** arr1 = [12], arr2 = [4]
**Output:** 4
**Explanation:** The list = [12 AND 4] = [4]. The XOR sum = 4.
**Constraints:**
* 1 <= arr1.length, arr2.length <= 105
* 0 <= arr1[i], arr2[j] <= 109