Class Solution


  • public class Solution
    extends Object
    1557 - Minimum Number of Vertices to Reach All Nodes\. Medium Given a** directed acyclic graph** , with `n` vertices numbered from `0` to `n-1`, and an array `edges` where edges[i] = [fromi, toi] represents a directed edge from node fromi to node toi. Find _the smallest set of vertices from which all nodes in the graph are reachable_. It's guaranteed that a unique solution exists. Notice that you can return the vertices in any order. **Example 1:** ![](https://assets.leetcode.com/uploads/2020/07/07/untitled22.png) **Input:** n = 6, edges = \[\[0,1],[0,2],[2,5],[3,4],[4,2]] **Output:** [0,3] **Explanation:** It's not possible to reach all the nodes from a single vertex. From 0 we can reach [0,1,2,5]. From 3 we can reach [3,4,2,5]. So we output [0,3]. **Example 2:** ![](https://assets.leetcode.com/uploads/2020/07/07/untitled.png) **Input:** n = 5, edges = \[\[0,1],[2,1],[3,1],[1,4],[2,4]] **Output:** [0,2,3] **Explanation:** Notice that vertices 0, 3 and 2 are not reachable from any other node, so we must include them. Also any of these vertices can reach nodes 1 and 4. **Constraints:** * `2 <= n <= 10^5` * `1 <= edges.length <= min(10^5, n * (n - 1) / 2)` * `edges[i].length == 2` * 0 <= fromi, toi < n * All pairs (fromi, toi) are distinct.
    • Constructor Detail

      • Solution

        public Solution()