Class Solution


  • public class Solution
    extends Object
    1318 - Minimum Flips to Make a OR b Equal to c\. Medium Given 3 positives numbers `a`, `b` and `c`. Return the minimum flips required in some bits of `a` and `b` to make ( `a` OR `b` == `c` ). (bitwise OR operation). Flip operation consists of change **any** single bit 1 to 0 or change the bit 0 to 1 in their binary representation. **Example 1:** ![](https://assets.leetcode.com/uploads/2020/01/06/sample_3_1676.png) **Input:** a = 2, b = 6, c = 5 **Output:** 3 **Explanation:** After flips a = 1 , b = 4 , c = 5 such that (`a` OR `b` == `c`) **Example 2:** **Input:** a = 4, b = 2, c = 7 **Output:** 1 **Example 3:** **Input:** a = 1, b = 2, c = 3 **Output:** 0 **Constraints:** * `1 <= a <= 10^9` * `1 <= b <= 10^9` * `1 <= c <= 10^9`
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • csb

        public static int csb​(int n)
      • minFlips

        public int minFlips​(int a,
                            int b,
                            int c)