Class Solution


  • public class Solution
    extends Object
    1028 - Recover a Tree From Preorder Traversal\. Hard We run a preorder depth-first search (DFS) on the `root` of a binary tree. At each node in this traversal, we output `D` dashes (where `D` is the depth of this node), then we output the value of this node. If the depth of a node is `D`, the depth of its immediate child is `D + 1`. The depth of the `root` node is `0`. If a node has only one child, that child is guaranteed to be **the left child**. Given the output `traversal` of this traversal, recover the tree and return _its_ `root`. **Example 1:** ![](https://assets.leetcode.com/uploads/2019/04/08/recover-a-tree-from-preorder-traversal.png) **Input:** traversal = "1-2--3--4-5--6--7" **Output:** [1,2,5,3,4,6,7] **Example 2:** ![](https://assets.leetcode.com/uploads/2019/04/11/screen-shot-2019-04-10-at-114101-pm.png) **Input:** traversal = "1-2--3---4-5--6---7" **Output:** [1,2,5,3,null,6,null,4,null,7] **Example 3:** ![](https://assets.leetcode.com/uploads/2019/04/11/screen-shot-2019-04-10-at-114955-pm.png) **Input:** traversal = "1-401--349---90--88" **Output:** [1,401,null,349,88,90] **Constraints:** * The number of nodes in the original tree is in the range `[1, 1000]`. * 1 <= Node.val <= 109
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • recoverFromPreorder

        public TreeNode recoverFromPreorder​(String traversal)