Class Solution


  • public class Solution
    extends Object
    1005 - Maximize Sum Of Array After K Negations\. Easy Given an integer array `nums` and an integer `k`, modify the array in the following way: * choose an index `i` and replace `nums[i]` with `-nums[i]`. You should apply this process exactly `k` times. You may choose the same index `i` multiple times. Return _the largest possible sum of the array after modifying it in this way_. **Example 1:** **Input:** nums = [4,2,3], k = 1 **Output:** 5 **Explanation:** Choose index 1 and nums becomes [4,-2,3]. **Example 2:** **Input:** nums = [3,-1,0,2], k = 3 **Output:** 6 **Explanation:** Choose indices (1, 2, 2) and nums becomes [3,1,0,2]. **Example 3:** **Input:** nums = [2,-3,-1,5,-4], k = 2 **Output:** 13 **Explanation:** Choose indices (1, 4) and nums becomes [2,3,-1,5,4]. **Constraints:** * 1 <= nums.length <= 104 * `-100 <= nums[i] <= 100` * 1 <= k <= 104
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • largestSumAfterKNegations

        public int largestSumAfterKNegations​(int[] nums,
                                             int k)