public class Solution extends Object
2493 - Divide Nodes Into the Maximum Number of Groups.
Hard
You are given a positive integer n representing the number of nodes in an undirected graph. The nodes are labeled from 1 to n.
You are also given a 2D integer array edges, where edges[i] = [ai, bi] indicates that there is a bidirectional edge between nodes ai and bi. Notice that the given graph may be disconnected.
Divide the nodes of the graph into m groups ( 1-indexed ) such that:
[ai, bi], if ai belongs to the group with index x, and bi belongs to the group with index y, then |y - x| = 1.Return the maximum number of groups (i.e., maximum m) into which you can divide the nodes. Return -1 if it is impossible to group the nodes with the given conditions.
Example 1:

Input: n = 6, edges = [[1,2],[1,4],[1,5],[2,6],[2,3],[4,6]]
Output: 4
Explanation: As shown in the image we:
We can see that every edge is satisfied. It can be shown that that if we create a fifth group and move any node from the third or fourth group to it, at least on of the edges will not be satisfied.
Example 2:
Input: n = 3, edges = [[1,2],[2,3],[3,1]]
Output: -1
Explanation: If we add node 1 to the first group, node 2 to the second group, and node 3 to the third group to satisfy the first two edges, we can see that the third edge will not be satisfied. It can be shown that no grouping is possible.
Constraints:
1 <= n <= 5001 <= edges.length <= 104edges[i].length == 21 <= ai, bi <= nai != bi| Constructor and Description |
|---|
Solution() |
| Modifier and Type | Method and Description |
|---|---|
int |
magnificentSets(int n,
int[][] edges) |
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