com.jn.langx.util.collection.stack

接口 Stack<E>

所有超级接口:

Collection<E>, Iterable<E>

所有已知实现类:

ListableStack, SimpleStack, ThreadSafeStack

public interface Stack<E>
extends Collection<E>

方法概要

限定符和类型	方法和说明
E	peek() Looks at the object at the top of this stack without removing it from the stack.
E	pop() Removes the object at the top of this stack and returns that object as the value of this function.
E	push(E item) Pushes an item onto the top of this stack.
int	search(Object o) Returns the 1-based position where an object is on this stack.

从接口继承的方法 java.util.Collection

add, addAll, clear, contains, containsAll, equals, hashCode, isEmpty, iterator, parallelStream, remove, removeAll, removeIf, retainAll, size, spliterator, stream, toArray, toArray

从接口继承的方法 java.lang.Iterable

forEach

方法详细资料

push

E push(E item)

Pushes an item onto the top of this stack. This has exactly the same effect as:

 addElement(item)

参数:

item - the item to be pushed onto this stack.

返回:

the item argument.

另请参阅:

Vector.addElement(E)

pop

E pop()

Removes the object at the top of this stack and returns that object as the value of this function.

返回:

The object at the top of this stack (the last item of the Vector object).

抛出:

EmptyStackException - if this stack is empty.

peek

E peek()

Looks at the object at the top of this stack without removing it from the stack.

返回:

the object at the top of this stack (the last item of the Vector object).

抛出:

EmptyStackException - if this stack is empty.

search

int search(Object o)

Returns the 1-based position where an object is on this stack. If the object o occurs as an item in this stack, this method returns the distance from the top of the stack of the occurrence nearest the top of the stack; the topmost item on the stack is considered to be at distance 1. The equals method is used to compare o to the items in this stack.

参数:

o - the desired object.

返回:

the 1-based position from the top of the stack where the object is located; the return value -1 indicates that the object is not on the stack.